Step-by-step example
Scenario: You have a single 12V 150Ah lead-acid battery. You want to run a 300W load. Your inverter is 90% efficient, and you set DoD to 50%.
Formula: Run Time = (Ah × V × DoD × Eff) / Load
- Total Wh = 150 Ah × 12 V = 1800 Wh total energy.
- Usable Wh = 1800 × 0.50 (DoD) × 0.90 (Efficiency) = 810 Wh.
- Run time = 810 Wh / 300 W = 2.7 hours.
- 0.7 hours × 60 = 42 minutes.
Result: 2 hours and 42 minutes.
Use cases
- Sizing a home inverter system for power outages.
- Determining UPS run time for server racks and critical IT infrastructure.
- Planning battery banks for RVs, camper vans, and boats.
- Off-grid cabin power planning.
- Calculating telecom tower emergency backup duration.
Assumptions & limitations
- This calculation is linear; it does not factor in Peukert's Law, which means very high discharge rates will reduce the effective capacity of lead-acid batteries.
- Assumes batteries are perfectly healthy and fully charged to 100% at the start.
- Inverter efficiency is assumed constant, though it drops significantly at very low or very high loads.
- Power factor for inductive loads is estimated; actual VA draw might be higher.
- Consult IEEE guidelines for stationary battery applications in enterprise settings.
Sources & references
- IEEE 485 - Recommended Practice for Sizing Lead-Acid Batteries
- IEC 62040 - UPS Standards
- Battery University - How to Calculate Runtime and Peukert's Law
- NIST Glossary - Ampere-hour