Step-by-step example
Scenario: You need 5 kWh/day using 540W panels, 5 sun hours, 80% efficiency, 24V system, 1 day autonomy, 50% DoD lead-acid battery.
Formula: Array W = (Daily kWh × 1000) ÷ (Peak sun hours × Loss factor)
- Array W = (5 × 1000) / (5 × 0.8) = 5000 / 4 = 1,250 W.
- Number of panels = 1,250 W / 540 W = 2.31 → round up to 3 panels.
- Daily Ah at 24V = 5000 Wh / 24V = 208.3 Ah.
- Battery Bank Ah = (208.3 × 1) / 0.50 = 416.6 Ah.
Result: Array: ~1250W (3 x 540W). Battery: 416 Ah @ 24V.
Use cases
- Sizing off-grid residential homes and cabins.
- Planning solar backup for rural telecom towers.
- Sizing agricultural solar water pumping systems.
- Rooftop residential grid-tie estimates.
- RV, camper, and boat power generation planning.
Assumptions & limitations
- Peak sun hours represent an annual average; winter months will produce less power.
- Calculations assume flat, unshaded roof space oriented optimally toward the sun.
- Inverter surging (motor starts) is not calculated here; ensure your inverter handles peak kW loads.
- Grid-tied systems do not require battery sizing and focus strictly on array wattage.
- Always consult local electrical codes and a licensed installer before purchasing equipment.
Sources & references
- NREL PVWatts methodology
- MNRE (Ministry of New & Renewable Energy) India
- IEC 61724 PV system performance
- ENERGY STAR Solar Guide