Step-by-step example
Scenario: A motor draws 8 kW real power and 10 kVA apparent power.
Formula: PF = kW / kVA
- PF = 8 / 10
- PF = 0.8 (or 80%)
Result: 0.8 power factor
Use cases
- Estimate real power from apparent power and power factor.
- Compare motor or transformer efficiency assumptions.
- Cross-check utility bill kW vs kVA relationships.
- Evaluate the impact of power factor on system sizing.
Assumptions & limitations
- Results are estimates and may be rounded; small differences are expected.
- Inputs assume steady-state values; transient and surge effects are not modeled.
- Voltage can vary by supply, load, and location; use measured values when possible.
- Power factor varies by load type; use a realistic value for inductive equipment.
- Wiring rules and safety codes vary by jurisdiction; consult a licensed electrician for installation decisions.
Sources & references
- OSHA Electrical Standards overview - Summarizes electrical safety standards and references NFPA 70/70E.
- ORNL Power Factor training (DOE) - Explains power factor and provides three-phase real power formula.
- OpenStax University Physics - Electrical energy and power - Defines electric power relationships such as P = IV and ties them to circuit variables.
- NIST Glossary - Joule - Defines the joule as a unit of energy and relates it to electrical quantities.